| the auroran sunset ( @ 2003-11-22 07:07:00 |
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the difference between a mathematician and a numerate
an amusing example of the difference between someone who can do maths, and someone who is nummerate!...
micina asked her readers how to solve the following..
A group of old ladies meet for an afternoon tea party. They bring all their cats. In all, there are 22 heads and 72 feet. How many old ladies and how many cats are in the room?
a) 6 old ladies and 16 cats
b) 7 old ladies and 15 cats
c) 8 old ladies and 14 cats
d) 9 old ladies and 13 cats
e) 10 old ladies and 12 cats
by the time i saw it this morning, someone had already explained how to solve this using simultaneous equations. admittedly i did vaguely considering doing that when i first saw it, but not for long.. here's my response:
alternatively, as you have the answers it may be quicker just to work out which fits..
eg. a) head: 6+16=22 (ok) feet: (6*2)+(16*4)=76 (wrong)
as they all subsusquent answers just add one human and subtract one cat, the number of heads doesn't change, and the number of feet goes down my two each time [-cat feet+human feet]. you need to subtract 4 from the feet, so the answer must be (c).
you may find that an easier method and much quicker!.. simultaneous equations are useful, but not always necessary. :-)
not often that i get examples of differences in response between a mathematician and a nummerate.. the mathematician [unless nummerate of course] will tend to do it the formula way every time no matter how long it takes, and is highly unlikely to see lower tech shortcuts.. for someone else's comments on this sort of thing see here.
update: it occured to me in the shower that my method is better even if there are no answers... make a stupid guess like 1 granny and 21 cats [idea making the heads right].. work out that this makes 86 feet. realise that this 14 too many. realise that this means swapping 7 cats into grannies.. voila: 8 grannies and 14 cats. still much quicker and easier than simultaneous equations. &=&